Q: sort's key and cmp parameters
gandalf at shopzeus.com
Thu Oct 1 20:05:21 CEST 2009
>> can be achieved (to a very good approximation at least) with
>> scrambled = some_list.sort(key=lambda x: random())
>> Is there a real-life sorting task that requires (or is far more
>> efficient with) cmp and can't be easily achieved with key and
> The core developers don't think there is one. list.sort() no longer supports
> the cmp parameter in 3.x.
BTW if you really want to sort a list then you can. Using keys or
values, it doesn't matter. The op's question has no practical usage.
REALLY looks like a homework.
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