slicing return iter?

StarWing weasley_wx at sina.com
Sat Oct 17 19:05:52 CEST 2009


On 10月17日, 下午11时56分, Arnaud Delobelle <arno... at googlemail.com> wrote:
> On Oct 17, 3:40 pm, StarWing <weasley... at sina.com> wrote:
>
>
>
> > hello everyone, I'm new here :-)
>
> > sometimes I want to iterate a part of a sequence. but don't want to
> > copy it. i.e.
>
> > a = list(...)
> > # now a is a list, and a[:] is another list, and so a[m:n]
> > # now we do something with the 0~len(a)-3 elements of a
> > for val in a[:-2]:
> >     #do something....
>
> > but, this will cause a copy on a, has some convenience way to get a
> > iter to iterate on a part of list?
>
> > i made this:
> > class iterslice:
> >     def __init__(self, list):
> >         self.list = list
>
> >     def __len__(self):
> >         return len(self.list)
>
> >     def __getitem__(self, slice):
> >         import itertools
> >         listlen = len(self.list)
> >         range = (((slice.start + listlen) % listlen) if slice.start
> > else 0,
> >                 ((slice.stop + listlen) % listlen) if slice.stop else
> > listlen,
> >                 slice.step)
> >         return itertools.islice(self.list, *range)
>
> > a = [1,2,3,4]
> > for i in iterslice(a)[:-1:2]:
> >     print i
>
> > my question is:
> >   - are there any *Standard* way to do this? (a buit-in function? a
> > module?)
> >   - are there any better implements?
>
> > thanks for attention :-)
>
> Check the itertools module.
>
> HTH
>
> --
> Arnaud

I had checked it for serval times. maybe it's my inattention :-(. but
what i could find the nearest thing is itertools.islice. but it can't
process negative index -- that's supported by slice. so I need
something, bind object with slice, and return a iter. I can find
anything like it...:-(



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