problem with re.MULTILINE

Necronymouse necronymouse at gmail.com
Sun Oct 18 21:49:00 CEST 2009


On 18 říj, 21:20, MRAB <pyt... at mrabarnett.plus.com> wrote:
> Necronymouse wrote:
> > Hello i ´ve got a little problem: I ´ve this text:
> >http://openpaste.org/en/secret/17343/pass-pythonand I need to parse
> > it. So i wrote this:
>
> > patternNode = re.compile("""
> > # Node (\w*).*
> > (.*)""", re.MULTILINE)
>
> > with open("test.msg", "r") as file:
> >     testData = file.read()
>
> > for Node in re.findall(patternNode, testData):
> >     print "Node:", Node[0]
> >     print Node
> > <<<
>
> > but it prints only one line from text. If i am using re.DOTALL it
> > wouldn´t print anything.. So don´t you know whre the problem is?
>
> I assume you mean that it's giving you only the first line of text of
> each node.
>
> "(.*)" will capture a single (and possibly empty) line of text.
>
> "(.+\n)" will capture a single non-empty line of text ending with a
> newline.
>
> I think you want to capture multiple non-empty lines, each line ending
> with a newline:
>
> patternNode = re.compile("""
> # Node (\w*).*
> ((?:.+\n)*)""", re.MULTILINE)
>
> > Sorry for my English - it´s not my native language...
>
> It's better than my Czech/Slovak (depending on what Google says)! :-)

Yeah this works ( ((?:.+\r\n)*) ), thanks.. It´s czech..



More information about the Python-list mailing list