Separate namespace from file hierarchy?
Peng Yu
pengyu.ut at gmail.com
Tue Oct 20 09:51:44 EDT 2009
Suppose I have the dirname/both.py, which has the definitions of
classes A and B. I can use this module in the following code.
#################
import dirname.both
a=dirname.both.A()
b=dirname.both.B()
####################
When the definitions of A and B become too long, it is better that I
put them in two different files (to improve the maintainability), for
example, dirname/A.py and dirname/B.py. Now, the code becomes
#################
import dirname.A
import dirname.B
a=dirname.A.A() #two A seems redundant
b=dirname.B.B() #two B seems redundant
####################
However, the last two lines are annoying to me, as 'A' and 'B' appears
twice, which seems redundant.
In C++, I can define namespace independent of file hierarchy (as shown
in the following code). I'm wondering if there is a way to make the
namespace separate from the file hierarchy in python.
#include <dirname/A.hpp>
#include <dirname/B.hpp>
int main() {
dirname::A a = dirname::A()
dirname::B b = dirname::B()
}
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