Copying a ZipExtFile

Moore, Mathew L MooreML at BATTELLE.ORG
Fri Oct 23 19:15:33 CEST 2009


Hello all,

A newbie here.  I was wondering why the following fails on Python 2.6.2 (r262:71605) on win32.  Am I doing something inappropriate?

Interestingly, it works in 3.1, but would like to also get it working in 2.6.

Thanks in advance,
--Matt


import io
import shutil
import tempfile
import zipfile

with tempfile.TemporaryFile() as f:
    # (Real code retrieves archive via urllib2.urlopen().)
    zip = zipfile.ZipFile(f, mode='w')
    zip.writestr('unknowndir/src.txt', 'Hello, world!')
    zip.close();

    # (Pretend we just downloaded the zip file.)
    f.seek(0)

    # Result of urlopen() is not seekable, but ZipFile requires a
    # seekable file.  Work around this by copying the file into a
    # memory stream.
    with io.BytesIO() as memio:
        shutil.copyfileobj(f, memio)
        zip = zipfile.ZipFile(file=memio)
        # Can't use zip.extract(), because I want to ignore paths
        # within archive.
        src = zip.open('unknowndir/src.txt')
        with open('dst.txt', mode='wb') as dst:
            shutil.copyfileobj(src, dst)


The last line throws an Error:


Traceback (most recent call last):
  File "test.py", line 25, in <module>
    shutil.copyfileobj(src, dst)
  File "C:\Python26\lib\shutil.py", line 27, in copyfileobj
    buf = fsrc.read(length)
  File "C:\Python26\lib\zipfile.py", line 594, in read
    bytes = self.fileobj.read(bytesToRead)
TypeError: integer argument expected, got 'long'





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