Copying a ZipExtFile
Moore, Mathew L
MooreML at BATTELLE.ORG
Fri Oct 23 19:15:33 CEST 2009
A newbie here. I was wondering why the following fails on Python 2.6.2 (r262:71605) on win32. Am I doing something inappropriate?
Interestingly, it works in 3.1, but would like to also get it working in 2.6.
Thanks in advance,
with tempfile.TemporaryFile() as f:
# (Real code retrieves archive via urllib2.urlopen().)
zip = zipfile.ZipFile(f, mode='w')
zip.writestr('unknowndir/src.txt', 'Hello, world!')
# (Pretend we just downloaded the zip file.)
# Result of urlopen() is not seekable, but ZipFile requires a
# seekable file. Work around this by copying the file into a
# memory stream.
with io.BytesIO() as memio:
zip = zipfile.ZipFile(file=memio)
# Can't use zip.extract(), because I want to ignore paths
# within archive.
src = zip.open('unknowndir/src.txt')
with open('dst.txt', mode='wb') as dst:
The last line throws an Error:
Traceback (most recent call last):
File "test.py", line 25, in <module>
File "C:\Python26\lib\shutil.py", line 27, in copyfileobj
buf = fsrc.read(length)
File "C:\Python26\lib\zipfile.py", line 594, in read
bytes = self.fileobj.read(bytesToRead)
TypeError: integer argument expected, got 'long'
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