How to get the realpath of a symbolic link?

Peng Yu pengyu.ut at gmail.com
Sat Oct 31 18:11:35 CET 2009


On Sat, Oct 31, 2009 at 11:26 AM, Emile van Sebille <emile at fenx.com> wrote:
> On 10/31/2009 12:03 AM Peng Yu said...
>>
>> Suppose that I have the following directory and files. I want to get
>> the canonical path of a file, a directory or a symbolic link.
>> For example, for 'b' below, I want to get its canonical path as
>> '/private/tmp/abspath/b'.
>
> So, why isn't realpath working for you?  It looks like it is, and it works
> that way here:
>
>>>> os.path.realpath('/home/emile/vmlinuz')
> '/root/vmlinuz-2.4.7-10'

My definition of 'realpath' is different from the definition of
'os.path.realpath'. But I'm not short what term I should use to
describe. I use the following example to show what I want.

In my example in the original post,

'/tmp/abspath/b' is a symbolic link to '/tmp/abspath/a' and '/tmp' is
a symbolic link to '/private/tmp'.

Therefore, I want to get '/private/tmp/abspath/b', rather than
'/private/tmp/abspath/a', as the canonical path of 'b'.

If the argument is a symbolic link os.path.realpath will return the
actually target of the symbolic link. However, I want the path of the
symbolic link rather than the path of the target.

Hope this is clear.



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