Q: sort's key and cmp parameters
Laszlo Nagy
gandalf at shopzeus.com
Thu Oct 1 14:05:21 EDT 2009
>> can be achieved (to a very good approximation at least) with
>>
>> scrambled = some_list.sort(key=lambda x: random())
>>
>> Is there a real-life sorting task that requires (or is far more
>> efficient with) cmp and can't be easily achieved with key and
>> reverse?
>>
>
> The core developers don't think there is one. list.sort() no longer supports
> the cmp parameter in 3.x.
>
LOL :-D
BTW if you really want to sort a list then you can. Using keys or
values, it doesn't matter. The op's question has no practical usage.
REALLY looks like a homework.
L
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