Is there a better way to code variable number of return arguments?
Jack Norton
jack at 0x6a.com
Thu Oct 8 14:26:37 EDT 2009
Dr. Phillip M. Feldman wrote:
> I currently have a function that uses a list internally but then returns the
> list items as separate return
> values as follows:
>
> if len(result)==1: return result[0]
> if len(result)==2: return result[0], result[1]
>
> (and so on). Is there a cleaner way to accomplish the same thing?
>
How about using yield and then iterate over the answer:
def some_fun():
\t for result in some_loopable_stuff:
\t\t yield result
Then call it thusly:
for i in some_fun()
result = i
-Jack (PS, sorry to the OP, you will get two of these -- I forgot to CC
the list)
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