Extracting patterns after matching a regex

Andreas Tawn andreas.tawn at ubisoft.com
Tue Sep 8 15:16:34 CEST 2009

> Hi,
> I need to extract a string after a matching a regular expression. For
> example I have the string...
> s = "FTPHOST: e4ftl01u.ecs.nasa.gov"
> and once I match "FTPHOST" I would like to extract
> "e4ftl01u.ecs.nasa.gov". I am not sure as to the best approach to the
> problem, I had been trying to match the string using something like
> this:
> m = re.findall(r"FTPHOST", s)
> But I couldn't then work out how to return the "e4ftl01u.ecs.nasa.gov"
> part. Perhaps I need to find the string and then split it? I had some
> help with a similar problem, but now I don't seem to be able to
> transfer that to this problem!
> Thanks in advance for the help,
> Martin

No need for regex.

s = "FTPHOST: e4ftl01u.ecs.nasa.gov"
If "FTPHOST" in s:
    return s[9:]



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