regex search with a space as the fist character
jack at 0x6a.com
Thu Sep 17 19:25:49 CEST 2009
Diez B. Roggisch wrote:
> Daniel Santos schrieb:
>>>>> print re.compile('u ').search(" u box2", 1)
>> <_sre.SRE_Match object at 0x7ff1d918>
>>>>> print re.compile(' u ').search(" u box2", 1)
>> Why ?
> because you start searching at the offset 1, which means you try to
> find " u " in "u box2" - and that's not found.
Couldn't you also just do:
re.compile('^\su')? That would match only if the first character is a
space and the second a 'u'.
I mean, I like to try and have the regexp do it all, instead of forcing
an index, not to mention trying to find the most specific regexp that
works(least generic -- I don't want any false positives). I also do
_not_ like having spaces in the regexp itself. If I need more than one
space I'll use '\s*' or '\s+'.
Also, whats the point of compiling the regexp if you use it only once?
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