Intercepting binding?
Xavier Ho
contact at xavierho.com
Wed Sep 23 21:10:53 EDT 2009
Here's a **very** hackish code I threw up together. It requires a lot of
manual checking and, I don't think it's practical at all.
###input:
default = set(locals())
class test():
def __init__(self):
self.name = str(self)
self.val = 'Mrra'
a = test()
user = set(locals()) - default
loc = dict(locals())
for item in loc.items():
if item[0] in user:
print(item)
###output:
('a', <__main__.test object at 0x0000000002D6A240>)
('default', {'__builtins__', '__name__', '__file__', '__doc__',
'__package__'})
('test', <class '__main__.test'>)
Cheers,
Ching-Yun "Xavier" Ho, Technical Artist
Contact Information
Mobile: (+61) 04 3335 4748
Skype ID: SpaXe85
Email: contact at xavierho.com
Website: http://xavierho.com/
On Thu, Sep 24, 2009 at 10:49 AM, Rhodri James
<rhodri at wildebst.demon.co.uk>wrote:
> On Thu, 24 Sep 2009 01:34:35 +0100, andrew cooke <andrew at acooke.org>
> wrote:
>
>
>> For example, I assume it's possible to somehow access the dictionary
>> for the current block, but I can't see how to do this after
>> assignment. If I do it in the Foo constructor, for example, "a" will
>> not yet be bound.
>>
>
> I apologise for failing to notice earlier that you know what you're
> talking about. I blame the hour :-)
>
> I'm not sure you can access the namespace dictionary of the "current
> block" (module?), that's the problem. Oh, except via locals(), which
> might do exactly what you're after depending. Excuse me, I'm being
> very dim tonight.
>
> --
> Rhodri James *-* Wildebeest Herder to the Masses
> --
> http://mail.python.org/mailman/listinfo/python-list
>
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