Partial directory search question

chad cdalten at gmail.com
Wed Sep 30 04:54:17 CEST 2009


On Sep 29, 7:52 pm, chad <cdal... at gmail.com> wrote:
> On Sep 29, 7:20 pm, Tim Chase <python.l... at tim.thechases.com> wrote:
>
> > > What's the sanest way to print out all the files in the directory that
> > > start with the underscore? Ie, I just want to list _1, _2, _3, _4.
>
> > I'd use a string's join() method to combine the results of a
> > list-comprehension or generator that filtered the output of
> > os.listdir() based on the startswith() method of the strings.
>
> > Left intentionally oblique and code-free because this sounds a
> > bit like a home-work problem.  If you're a python coder, that
> > should make pretty decent sense and be a one-liner to implement.
>
> > -tkc
>
> Okay, sorry for the delay to the response. I got side tracked trying
> to stalk, I mean talk to the 59 year old neighbor girl. Anyways, I
> couldn't get it to one in one line. Here is what I did...
>
> % more rec.py
> #!/usr/local/bin/python
>
> import os
> import time
>
> for filename in os.listdir("/usr/bbs/confs/september"):
>      #stat = os.stat(filename)
>      if filename.startswith("_"):
>         print filename
>
> ./rec.py
> _1
> _2
> _3
> _4
> _5
> _6
> _7
> _8
>
> It correctly prints out all the files in the directory that start with
> an underscore.


er *couldn't get it into a one liner*.



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