Quick compare string to list
Emile van Sebille
emile at fenx.com
Wed Sep 30 21:06:14 CEST 2009
On 9/30/2009 11:36 AM Scooter said...
> I'm reading in a text file, and for each line in the file, I'm looking
> for the existence of phrases from a list. The list contains approx.
> 120 items currently but will most likely grow. This procedure itself
> is not the main function of my program and only grew out of the need
> to reformat certain phrases I'm finding in a file before re-outputting
> it. But as I suspected, this searching of the lists slows the whole
> process way way down. Was looking for ideas of a better way to do
> I basically have
> code that reads in the flat file into string 'flatfileString'
> for listitem in mylist:
> if flatfileString.count(listitem):
> ...whatever...I found it.
Whatever you do next to reformat those certain phrases will require a
second scan which doubles the time involved, and as you don't save the
count anyway, if mylist were exchange couplets you could use replace
directly. Something like:
mylist = [('Chevy','Chevrolet'),
(... etc... )
for wrong,right in mylist:
Flavor to taste,
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