How to access args as a list?

Grant Edwards invalid at invalid.invalid
Sat Apr 3 21:14:24 EDT 2010

On 2010-04-03, kj < at> wrote:
> In <hp8h73$k17$1 at> kj < at> writes:
>>Suppose I have a function with the following signature:
>>def spam(x, y, z):
>>    # etc.
>>Is there a way to refer, within the function, to all its arguments
>>as a single list?  (I.e. I'm looking for Python's equivalent of
>>Perl's @_ variable.)
>>I'm aware of locals(), but I want to preserve the order in which
>>the arguments appear in the signature.
>>My immediate aim is to set up a simple class that will allow me to
>>iterate over the arguments passed to the constructor (plus letS me
>                                                        ^^^^^^^^^^^^
>>refer to these individual arguments by their names using an
>  ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
>>instance.attribute syntax, as usual).
>  ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
> The underlined portion explains why __init__(self, *args) fails to
> fit the bill.

then add the line below:

   x,y,z = *args


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