How to access args as a list?
no.email at please.post
Mon Apr 5 20:49:08 CEST 2010
In <4bb802f7$0$8827$c3e8da3 at news.astraweb.com> Steven D'Aprano <steve at REMOVE-THIS-cybersource.com.au> writes:
>On Sat, 03 Apr 2010 22:58:43 +0000, kj wrote:
>> Suppose I have a function with the following signature:
>> def spam(x, y, z):
>> # etc.
>> Is there a way to refer, within the function, to all its arguments as a
>> single list? (I.e. I'm looking for Python's equivalent of Perl's @_
>Does this help?
>>>> def spam(a, b, c=3, d=4):
>('a', 'b', 'c', 'd')
That's very handy. Thanks!
>The hardest part is having the function know its own name.
Indeed. Why Python does not provide this elmentary form of
introspection as a built-in variable is extremely puzzling to me
(even--no, *more so*--after reading PEP 3130).
>I see that you are already using the inspect module. That almost
>certainly is the correct approach. I'd be surprised if inspect is too
>heavyweight, but if it is, you can pull out the bits you need into your
That's a good idea. Thanks!
More information about the Python-list