lambda with floats

[Peter Pearson]

On Tue, 06 Apr 2010 23:16:18 -0400, monkeys paw <monkey at joemoney.net> wrote:
> I have the following acre meter which works for integers,
> how do i convert this to float? I tried
>
> return float ((208.0 * 208.0) * n)
>
> >>> def s(n):
> ... 	return lambda x: (208 * 208) * n
> ...
> >>> f = s(1)
> >>> f(1)
> 43264
> >>> 208 * 208
> 43264
> >>> f(.25)
> 43264

The expression "lambda x: (208 * 208) * n" is independent of x.
Is that what you intended?


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