error when printing a UTF-8 string (python 2.6.2)
fab at slick.airforce-one.org
fab at slick.airforce-one.org
Wed Apr 21 04:09:48 EDT 2010
Hello.
I read a string from an utf-8 file:
fichierLaTeX = codecs.open(sys.argv[1], "r", "utf-8")
s = fichierLaTeX.read()
fichierLaTeX.close()
I can then print the string without error with 'print s'.
Next I parse this string:
def parser(s):
i = 0
while i < len(s):
if s[i:i+1] == '\\':
i += 1
if s[i:i+1] == '\\':
print "backslash"
elif s[i:i+1] == '%':
print "pourcentage"
else:
if estUnCaractere(s[i:i+1]):
motcle = ""
while estUnCaractere(s[i:i+1]):
motcle += s[i:i+1]
i += 1
print "mot-clé '"+motcle+"'"
but when I run this code, I get this error:
Traceback (most recent call last):
File "./versOO.py", line 115, in <module>
parser(s)
File "./versOO.py", line 105, in parser
print "mot-clé '"+motcle+"'"
UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in
position 6: ordinal not in range(128)
What must I do to solve this?
Thanks!
--
Fabrice DELENTE
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