lambda with floats

[Patrick Maupin]

On Apr 6, 11:04 pm, Patrick Maupin <pmau... at gmail.com> wrote:
> On Apr 6, 10:16 pm, monkeys paw <mon... at joemoney.net> wrote:
>
> > I have the following acre meter which works for integers,
> > how do i convert this to float? I tried
>
> > return float ((208.0 * 208.0) * n)
>
> >  >>> def s(n):
> > ...     return lambda x: (208 * 208) * n
> > ...
> >  >>> f = s(1)
> >  >>> f(1)
> > 43264
> >  >>> 208 * 208
> > 43264
> >  >>> f(.25)
> > 43264
>
> Not sure why you are returning a lambda (which is just a function that
> does not have a name) from an outer function.
>
> A function that does this multiplication would simply be:
>
> def s(n):
>     return 208.0 * 208.0 * n
>
> Regards,
> Pat


I realized I didn't show the use.  A bit different than what you were
doing:

>>> def s(n):
...     return 208.0 * 208.0 * n
...
>>> s(1)
43264.0
>>> s(0.5)
21632.0
>>> s(3)
129792.0


I'm not sure exactly what you mean by "acre meter" though; this
returns the number of square feet in 'n' acres.

Regards,
Pat