lambda with floats

[monkeys paw]

On 4/9/2010 3:43 AM, Bas wrote:
> On Apr 7, 6:15 am, Patrick Maupin<pmau... at gmail.com>  wrote:
>> I should stop making a habit of responding to myself, BUT.  This isn't
>> quite an acre in square feet.  I just saw the 43xxx and assumed it
>> was, and then realized it couldn't be, because it wasn't divisible by
>> 10.  (I used to measure land with my grandfather with a 66 foot long
>> chain, and learned at an early age that an acre was 1 chain by 10
>> chains, or 66 * 66 * 10 = 43560 sqft.)
>> That's an exact number, and 208 is a poor approximation of its square
>> root.
>
> There is no need to remember those numbers for the imperially
> challenged people:
>
> In [1]: import scipy.constants as c

scipy.constants ??

doesn't work for me.

>
> In [2]: def acre2sqft(a):
>     ...:     return a * c.acre / (c.foot * c.foot)
>     ...:
>
> In [3]: acre2sqft(1)
> Out[3]: 43560.0
>
>
> Cheers,
> Bas