Python 2.7 re.IGNORECASE broken in re.sub?
alex at moreati.org.uk
Mon Aug 16 02:36:07 CEST 2010
On Aug 16, 1:07 am, Steven D'Aprano <st... at REMOVE-THIS-
> You're passing re.IGNORECASE (which happens to equal 2) as a count
> argument, not as a flag. Try this instead:
> >>> re.sub(r"python\d\d" + '(?i)', "Python27", t)
Basically right, but in-line flags must be placed at the start of a
pattern, or the result is undefined. Also in Python 2.7 re.sub() has a
Python 2.7.0+ (release27-maint:83286, Aug 16 2010, 01:25:58)
[GCC 4.4.3] on linux2
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>>> import re
>>> t = 'Python26'
>>> re.sub(r'(?i)python\d\d', 'Python27', t)
>>> re.sub(r'python\d\d', 'Python27', t, flags=re.IGNORECASE)
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