Unsupported Format Character '&' (0x26)
__peter__ at web.de
Thu Aug 19 13:35:01 CEST 2010
Andrew Evans wrote:
> On Wed, Aug 18, 2010 at 4:35 PM, Andrew Evans <randrange at gmail.com> wrote:
>> I get an error message "Unsupported Format Character '&' (0x26)" I
>> narrowed it down to these two variables
>> any idea how to fix it?
>> SEARCH_URL_0 = "http://search.yahoo.com/search...?p=%(query)..."
> nvm I got it by adding s and d respectively after each value eg %(query)s
If you want to handle this reliably have a look at urllib.urlencode().
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