matplotlib pyplot contourf with 1-D array (vector)
rda.selin at gmail.com
Thu Aug 26 14:58:14 CEST 2010
On Aug 26, 1:52 am, Dennis Lee Bieber <wlfraed at ix.netcom.com> wrote:
> On Wed, 25 Aug 2010 14:57:33 -0700 (PDT), becky_s <rda.selin at gmail.com>
> declaimed the following in gmane.comp.python.general:
> > px,py = p(mesolon, mesolat)
> For my elucidation, what does that p(x,y) actually do? Especially
> as you appear to expect the result to be split into separate x and y
> afterwards? I can't find it defined in either matplotlib nor numpy.
p was declared as a basemap object in the previous statement, which
sets up a map projection. Calling p(mesolon, mesolat) converts those
lons, lats to units in that map projection and stores them in px,py.
for more info on basemap.)
> > pyplot_api.html#matplotlib.pyplot.contourf) I thought that as long as
> > px, py, and rain are the same dimensions, everything should be fine.
> And are they? You don't demonstrate that you've checked for that
I did a simple print px.shape, rain.shape, etc. to check. They are
all size (135,).
> > Apparently that is not the case? If 1D arrays are not allowed in
> > contourf, then how can I change my data into a 2D array?
> Also note (jumping to your follow up) that contourf is described as
> having a potential problem with masked arrays (whatever those are) for
My problem isn't with the masked arrays as much as it is with rain
being a 1D array. IDL can handle contouring 1D arrays with missing
variables lickety-split, so I was really hoping Python could as well.
Also, numpy.ma is the masked array library. See
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