lpr via subprocess in 2.4

[loial]

Thanks...that worked.

I have also been trying to get the return code and standard error.

How do I access these?

#!/usr/bin/python
import os
import subprocess
process=subprocess.Popen(['lpr', '-P' ,'raserlpr','/etc/hosts'],
shell=False, stdout=subprocess.PIPE, stderr=subprocess.PIPE)

print process.communicate()








On 4 Aug, 12:08, Peter Otten <__pete... at web.de> wrote:
> loial wrote:
> > I am am trying to run the following command via subprocess
>
> > lpr -P printqueue filetoprint
>
> > I cannot seem to get it to work and return stderr
>
> > I think the issue is how to specify the arguments
>
> > I am trying
>
> > subprocess.Popen(['lpr -P' ,'laserlpr','/etc/hosts'], shell=False)
>
> This looks for an executable called "lpr -P"; try
>
> subprocess.Popen(['lpr', '-P' ,'laserlpr','/etc/hosts'], shell=False)
>
>
>
> > but get error :
>
> > Traceback (most recent call last):
> >   File "testopen.py", line 6, in ?
> >     subprocess.Popen(['lpr -P' ,'laserlpr','/etc/hosts'], shell=False)
> >   File "/usr/python2.4/lib/python2.4/subprocess.py", line 558, in __in
> > it__
> >     errread, errwrite)
> >   File "/usr/python2.4/lib/python2.4/subprocess.py", line 991, in _exe
> > cute_child
> >     raise child_exception
> > OSError: [Errno 2] No such file or directory- Hide quoted text -
>
> - Show quoted text -