Using a function for regular expression substitution
Roy Smith
roy at panix.com
Sun Aug 29 11:10:37 EDT 2010
In article
<9170aad0-478a-4222-b6e2-88d00899d8b4 at t2g2000yqe.googlegroups.com>,
naugiedoggie <michael.a.powe at gmail.com> wrote:
> Hello,
>
> I'm having a problem with using a function as the replacement in
> re.sub().
>
> Here is the function:
>
> def normalize(s) :
> return
> urllib.quote(string.capwords(urllib.unquote(s.group('provider'))))
I read though this entire post, and I'm not quite sure what you're
asking. May I suggest that you need to break this down into smaller
pieces and find a minimal test case.
I'm guessing this is a problem with the regex processing. To prove
that, strip away everything else and verify that part in isolation.
Compile your regex, and match it against a string that you expect it to
match. Then, examine the groups returned by the match object. If
they're not what you expect, then re-post your question, with just this
minimal test code.
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