Change one list item in place

[Gnarlodious]

On Dec 1, 6:23 am, Jean-Michel Pichavant <jeanmic... at sequans.com>
wrote:
> what about
>
> def query():
>     return ["Formating only {0} into a string".format(sendList()[0])] +
> sendList()[1:]

However this solution calls sendList() twice, which is too processor
intensive.

Thanks for all the ideas, I've resigned myself to unpacking a tuple
and reassembling it.

-- Gnarlie
http://Sectrum.com