type(d) != type(d.copy()) when type(d).issubclass(dict)

[Benjamin Kaplan]

On Dec 24, 2010 4:40 PM, "Flávio Lisbôa" <flisboa.costa at gmail.com> wrote:
>>
>>  copy, here, is a dict method. It will create a dict.
>> If you really need it, you could try this:
>>
>> import copy
>> class neodict(dict):
>>    def copy(self):
>>        return copy.copy(self)
>>
>> d = neodict()
>> print type(d)
>> dd = d.copy()
>> print type(dd)
>
>
> One more gotcha to python... OO in python is strange :p
>
> IMO, if i subclass a class, all instance methods from a subclass instance
should work with the subclass. But i'm guessing python doesn't make this
distinction of instance/class methods like some other languages do (unless
one uses annotations, what appears to be not the case with the dict class).
>

This isn't at all unique to Python. You'd get the same results in java or
any other language.

public class Foo {
    int a;
    public Foo(int a) {
        this.a = a;
    }
    public Foo clone() {
        return new Foo(this.a);
    }
}

public class Bar extends Foo {
   public Bar() {
        super(0);
   }
}

What type do you think (new Bar()).clone() is going to return?

> Not that it inhibits me on using python in any way, in fact i do use
python for my projects. I'm new to it, and I like some of its features, but
some others are rather strange.
>
> --
> http://mail.python.org/mailman/listinfo/python-list
>
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