Is there a simple way to find the list index to the max value?
tomf.sessile at gmail.com
Wed Feb 17 05:44:09 CET 2010
On 2010-02-16 11:44:45 -0800, aahz at pythoncraft.com (Aahz) said:
> In article <4B7A91B1.6030301 at lonetwin.net>, steve <steve at lonetwin.net> wrote:
>> On 02/16/2010 05:49 PM, W. eWatson wrote:
>>> See Subject. a = [1,4,9,3]. Find max, 9, then index to it, 2.
>> The most obvious would be a.index(max(a)). Is that what you wanted ?
> The disadvantage of that is that it's O(2N) instead of O(N).
I don't think you understand order notation. There's no such thing as O(2N).
To answer the original question, how about:
max(enumerate(l), key=lambda x: x)
As to whether this is faster than index(max()), you'd have to time it.
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