best way to create a dict from string
Tim Arnold
tim.arnold at sas.com
Thu Feb 18 11:20:44 EST 2010
Hi,
I've got some text to parse that looks like this
text = ''' blah blah blah
\Template[Name=RAD,LMRB=False,LMRG=True]{tables}
ho dee ho
'''
I want to extract the bit between the brackets and create a dictionary.
Here's what I'm doing now:
def options(text):
d = dict()
options = text[text.find('[')+1:text.find(']')]
for k,v in [val.split('=') for val in options.split(',')]:
d[k] = v
return d
if __name__ == '__main__':
for line in text.split('\n'):
if line.startswith('\\Template'):
print options(line)
is that the best way or maybe there's something simpler? The options will
always be key=value format, comma separated.
thanks,
--TIm
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