Replace various regex

[Martin]

On Feb 12, 7:57 pm, McColgst <mccol... at gmail.com> wrote:
> On Feb 12, 2:39 pm, Martin <mdeka... at gmail.com> wrote:
>
>
>
>
>
> > Hi,
>
> > I am trying to come up with a more generic scheme to match and replace
> > a series of regex, which look something like this...
>
> > 19.01,16.38,0.79,1.26,1.00   !  canht_ft(1:npft)
> > 5.0, 4.0, 2.0, 4.0, 1.0      !  lai(1:npft)
>
> > Ideally match the pattern to the right of the "!" sign (e.g. lai), I
> > would then like to be able to replace one or all of the corresponding
> > numbers on the line. So far I have a rather unsatisfactory solution,
> > any suggestions would be appreciated...
>
> > The file read in is an ascii file.
>
> > f = open(fname, 'r')
> > s = f.read()
>
> > if CANHT:
> >     s = re.sub(r"\d+.\d+,\d+.\d+,\d+.\d+,\d+.\d+,\d+.\d+   !
> > canht_ft", CANHT, s)
>
> > where CANHT might be
>
> > CANHT = '115.01,16.38,0.79,1.26,1.00   !  canht_ft'
>
> > But this involves me passing the entire string.
>
> > Thanks.
>
> > Martin
>
> If I understand correctly, there are a couple ways to do it.
> One is to use .split() and split by the '!' sign, given that you wont
> have more than one '!' on a line. This will return a list of the words
> split by the delimiter, in this case being '!', so you should get back
> (19.01,16.38,0.79,1.26,1.00  ,  canht_ft(1:npft) )  and you can do
> whatever replace functions you want using the list.
>
> check out split:http://docs.python.org/library/stdtypes.html#str.split
>
> Another, is in your regular expression, you can match the first part
> or second part of the string by specifying where the '!' is,
> if you want to match the part after the '!' I would do something like
> r"[^! cahnt_ft]", or something similar (i'm not particularly up-to-
> date with my regex syntax, but I think you get the idea.)
>
> I hope I understood correctly, and I hope that helps.
>
> -sean

Hi I like the second suggestion, so this wouldn't rely on me having to
match the numbers only the string canht for example but still allow me
to replace the whole line, is that what you mean?

I tried it and the expression seemed to replace the entire file, so
perhaps i am doing something wrong. But in principle I think that
might be a better scheme than my current one. i tried

if CANHT:
    #s = re.sub(r"\d+.\d+,\d+.\d+,\d+.\d+,\d+.\d+,\d+.\d+   !
canht_ft", CANHT, s)
    s = re.sub(r"[^!  canht_ft]", CANHT, s)