mod, modulo and % under 2.4 and 2.5

Jan Kaliszewski zuo at chopin.edu.pl
Fri Jan 1 03:04:08 CET 2010


01-01-2010 o 02:30:20 W. eWatson <wolftracks at invalid.com> wrote:

> About a year ago, I wrote a program that used mod() for modulo under  
> 2.5. Apparently, % is also acceptable, but the program works quite well.  
> I turned the program over to someone who is using 2.4, and apparently  
> 2.4 knows nothing about mod(). Out of curiosity, what library is  
> mod(a,b)(two args) in? It doesn't seem to be in numpy. It seems to be  
> built-in. If so, why isn't it both 2.4 and 2.5?

???

There is no builtin mod() function at all, but there are (in Py 2.4, 2.5,
2.6, 3.0 and 3.1):
* builtin '%' and '%=' operators
* builtin divmod()
* in 'operator' module: mod() or __mod__() [the same] -- equivalents of
   '%' operator
* in 'math' module: fmod() function

Additionaly, since Py 2.5 in 'operator' module there is imod() and
__imod__() [the same] -- equivalents of '%=' operator.

Cheers,
*j



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