[220.127.116.11/dictionary] Change sorting order?
neilc at norwich.edu
Fri Jan 22 16:57:07 CET 2010
On 2010-01-22, Steven D'Aprano <steve at REMOVE-THIS-cybersource.com.au> wrote:
> On Fri, 22 Jan 2010 13:35:26 +0000, Neil Cerutti wrote:
>> On 2010-01-22, Gilles Ganault <nospam at nospam.com> wrote:
>>> I use a dictionary to keep a list of users connected to a web site.
>>> To avoid users from creating login names that start with digits in
>>> order to be listed at the top, I'd like to sort the list differently
>>> every minute so that it'll start with the next letter, eg. display the
>>> list from A...Zdigits the first time, then B...ZAdigits, etc.
>> Resorting is more work than is needed. Just choose a different starting
>> index each time you display the names, and set up your lister to
>> wrap-around to your arbitrary starting index.
> The original poster's requirement is to start at a new *letter*
> each time, not whatever name happens to be at index N.
> Unless you can predict what index to use for (say) names
> starting with "B", then your scheme doesn't work. In order to
> find that index, you have to do a linear search of the list
> after every sort, turning sorting into O(N**2) instead of
> O(N*log N).
O(N*Log N) + O(N) == O(N**2)?
Besides, the idea was to avoid sorting altogether.
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