integer and string compare, is that correct?

[Hellmut Weber]

Hi,
thanks to all who answered.

I'm using Python 2.6.5 on my machine and consulted the corresponding 
documentation.
I do appreciate the modified definition of python 3, that seems much 
more reasonable.

Thanks for indicating.

Greetings from Munich in Winter

Hellmut

Am 10.01.2010 17:34, schrieb Nobody:
> Hellmut Weber wrote:
>
>>> being a causal python user (who likes the language quite a lot)
>>> it took me a while to realize the following:
>
>>>   >>>  max = '5'
>>>   >>>  n = 5
>>>   >>>  n>= max
>>> False
>>
>>> Section 5.9 Comparison describes this.
>>>
>>> Can someone give me examples of use cases
>
> Peter Otten wrote:
>
>> The use cases for an order that works across types like int and str are weak
>> to non-existent. Implementing it was considered a mistake and has been fixed
>> in Python 3:
>
>>>>> 5>  "5"
>> Traceback (most recent call last):
>>    File "<stdin>", line 1, in<module>
>> TypeError: unorderable types: int()>  str()
>
> If you actually need to perform comparisons across types, you can rely
> upon the fact that tuple comparisons are non-strict and use e.g.:
>
> 	>  a = 5
> 	>  b = '5'
> 	>  (type(a).__name__, a)<  (type(b).__name__, b)
> 	True
> 	>  (type(a).__name__, a)>  (type(b).__name__, b)
> 	False
>
> The second elements will only be compared if the first elements are equal
> (i.e. the values have the same type).
>

-- 
Dr. Hellmut Weber         mail at hellmutweber.de
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