Fractional Hours from datetime?

[M.-A. Lemburg]

W. eWatson wrote:
> Maybe there's a more elegant way to do this. I want to express the
> result of datetime.datetime.now() in fractional hours.
> 
> Here's one way.
> 
> dt=datetime.datetime.now()
> xtup = dt.timetuple()
> h = xtup[3]+xtup[4]/60.0+xtup[5]/3600.00+xtup[6]/10**6
> #  now is in fractions of an hour

Here's how you'd do that with mxDateTime:

>>> from mx.DateTime import now
>>> now().abstime / 3600.0
13.17341068830755

.abstime gives you the time in fractional seconds.

http://www.egenix.com/products/python/mxBase/mxDateTime/

-- 
Marc-Andre Lemburg
eGenix.com

Professional Python Services directly from the Source  (#1, Jan 11 2010)
>>> Python/Zope Consulting and Support ...        http://www.egenix.com/
>>> mxODBC.Zope.Database.Adapter ...             http://zope.egenix.com/
>>> mxODBC, mxDateTime, mxTextTools ...        http://python.egenix.com/
________________________________________________________________________

::: Try our new mxODBC.Connect Python Database Interface for free ! ::::


   eGenix.com Software, Skills and Services GmbH  Pastor-Loeh-Str.48
    D-40764 Langenfeld, Germany. CEO Dipl.-Math. Marc-Andre Lemburg
           Registered at Amtsgericht Duesseldorf: HRB 46611
               http://www.egenix.com/company/contact/