Closures in metaclasses
Arnaud Delobelle
arnodel at googlemail.com
Thu Jan 21 13:24:32 EST 2010
Falcolas <garrickp at gmail.com> writes:
> I'm running into an issue with closures in metaclasses - that is, if I
> create a function with a closure in a metaclass, the closure appears
> to be lost when I access the final class. I end up getting the text
> 'param' instead of the actual tags I am expecting:
>
> ALL_TAGS = ['a', 'abbr', 'acronym', 'address', 'applet', 'b', 'bdo',
> 'big'] #snip
>
> def _tag_meta(name, bases, dict_):
> for tag in ALL_TAGS:
> def generic_tag(*args, **kwargs):
> return Tag._generate_tag(tag, *args, **kwargs)
> #generic_tag = eval("lambda *args, **kwargs: Tag._generate_tag
> ('%s', *args, **kwargs)" % tag)
> dict_[tag] = staticmethod(generic_tag)
> return type(name, bases, dict_)
This is almost a FAQ and has nothing to do with metaclasses. The
simplest solution usually involves adding a default argument 'tag=tag'
to the function you define (here, generic_tag), but you can't do this
here because you have a **kwargs argument. Instead, you can use a
closure and do this for example:
def factory(tag):
def generic_tag(*args, **kwargs):
return Tag._generate_tag(tag, *args, **kwargs)
return generic_tag
def _tag_meta(name, bases, dict_):
for tag in ALL_TAGS:
dict_[tag] = staticmethod(factory(tag))
return type(name, bases, dict_)
Then your Tag example class will work as you expect:
class Tag(object):
__metaclass__ = _tag_meta
@staticmethod
def _generate_tag(tag_name, *args, **kwargs):
# Does the expected, following is just for the example's sake
return tag_name
I am sure that there are plenty of discussions of this issue in the
archives of c.l.python. I just can't think of a good keyword to google
it ATM.
However, I am usure about why you are using a metaclass.
HTH
--
Arnaud
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