[2.5.1.1/dictionary] Change sorting order?

[Gilles Ganault]

On Fri, 22 Jan 2010 09:49:32 -0500, Dave Angel <davea at ieee.org> wrote:
>Seems to me the other solutions I've seen so far are more complex than 
>needed.  I figure you either want an unordered list, in which case you 
>could use random.shuffle(), or you want a list that's sorted, but starts 
>somewhere in the middle, at an arbitrary place, goes to the end, and 
>wraps back to the beginning.  So use random.randint() to choose an index 
>within the list, and concatenate two slices of the list, based on that 
>index in reverse order.

Yes, this is exactly what I need: Start listing items from a given
index (actually, using a character since the list contains names) all
the way to the end of the list; If the character wasn't the very
first, go back to the first time and display the list until we get to
the current character.

Python is so feature-rich, I'm sure there's a much simpler way to do
this than this crappy code of mine:

=============
connected = []
connected.append("0dummy")
connected.append("aa")
connected.append("bb")
connected.append("cc")

index = 0
for item in connected:
	#For testing purposes;
	#Final code will read/increment character from file
	if item[index] == "b":
		break
	else:
		index = index + 1

#Print items between current character and end of list
tempindex = index
while(tempindex < len(connected)):
	print connected[tempindex]
	tempindex = tempindex + 1

#if current letter not first character,
#display beginning of list up to current character
if index != 0:
	tempindex = 0
	while tempindex < index:
		print connected[tempindex]
		tempindex = tempindex + 1
=============

Thank you for any help