Symbols as parameters?
Roald de Vries
rdv at roalddevries.nl
Fri Jan 29 03:08:56 EST 2010
On Jan 29, 2010, at 2:30 AM, Steven D'Aprano wrote:
> On Thu, 28 Jan 2010 17:01:38 +0100, Roald de Vries wrote:
>> Question out of general interest in the language: If I would want to
>> generate such functions in a for-loop, what would I have to do? This
>> doesn't work:
>>
>> class Move(object):
>> def __call__(self, direction):
>> return direction
>>
>> move = Move()
>>
>> for f in ['up', 'down', 'right', 'left']:
>> move.__dict__[f] = lambda: move(f)
>>
>> ... because now 'move.up()' returns 'left' because thats the current
>> value of f. Is there a way to 'expand' f in the loop? Or a reason
>> that
>> you never should use this?
>
>
> Possibly the simplest way is to use Python's handling of default
> values
> to get the result you want:
>
> for f in ['up', 'down', 'right', 'left']:
> move.__dict__[f] = lambda f=f: move(f)
This still leaves open the possibility of move.up('down') resulting in
move('down'), but for the rest I like it.
> BTW, there's no need to explicitly reference move.__dict__:
>
> for f in ['up', 'down', 'right', 'left']:
> setattr(move, f, lambda f=f: move(f))
I expected something like that. Thanks.
Roald
More information about the Python-list
mailing list