default behavior

[Peter Otten]

wheres pythonmonks wrote:

> How do I build an "int1" type that has a default value of 1?
> [Hopefully no speed penalty.]
> I am thinking about applications with collections.defaultdict.

>>> from collections import defaultdict
>>> d = defaultdict(1 .conjugate)
>>> d["x"] += 2
>>> d["x"]
3

Isn't that beautiful? Almost like home;)

It is also fast:

$ python -m timeit -s"one = lambda: 1" "one()"
1000000 loops, best of 3: 0.213 usec per loop
$ python -m timeit -s"one = 1 .conjugate" "one()"
10000000 loops, best of 3: 0.0972 usec per loop

Micro-optimisation, the best excuse for ugly code...

Peter