Build unordered list in HTML from a python list

[Remi Carton]

> Dear list members
> 
> I have this python list that represets a sitemap:
> 
> tree = [{'indent': 1, 'title':'Item 1', 'hassubfolder':False},
>          {'indent': 1, 'title':'Item 2', 'hassubfolder':False},
>          {'indent': 1, 'title':'Folder 1', 'hassubfolder':True},
>          {'indent': 2, 'title':'Sub Item 1.1', 'hassubfolder':False},
>          {'indent': 2, 'title':'Sub Item 1.2', 'hassubfolder':False},
>          {'indent': 1, 'title':'Item 3', 'hassubfolder':False},
>          {'indent': 1, 'title':'Folder 2', 'hassubfolder':True},
>          {'indent': 2, 'title':'Sub Item 2.1', 'hassubfolder':False},
>          {'indent': 2, 'title':'Folder 2.1', 'hassubfolder':True},
>          {'indent': 3, 'title':'Sub Item 2.1.1', 'hassubfolder':False},
>          {'indent': 3, 'title':'Sub Item 2.1.2', 'hassubfolder':False},
> 
> If an item of the list has 'True' for the 'hassubfolder' key than a new 
> "<ul><li>" must be created instead of "</li>" after its title. (See 
> "Folder 2" node in the HTML code above.

Or you can change your list to a dict with a tree structure and use 
recursion instead of a stack:

tree = [ 
                { 'title': 'Item 1', 'children': [] }, 
                { 'title': 'Item 2', 'children': [] }, 
                { 'title': 'Folder 1', 'children': [ 
                                                                { 'title': 
'sub item 1.1',
 'children' : [],
                                                                },
                                                                { 'title': 
'Folder 1.1',
 'children' : [ .. ],
                                                                },
                                                                ] }, 
       ]


and something like:

def displayListItem(i):
        print '<li>%s' % i['title']
        if i['children']:
                print '<ul>'
                for c in i['children']:
                        displayListItem(c)
                print '</ul>'
        print </li>


you might also use recursion with your existing list, by 'pop'ing the 
first item and passing the rest of the list.

Remi
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