Conditional based on whether or not a module is being used
Pete Emerson
pemerson at gmail.com
Fri Mar 5 14:24:44 EST 2010
In a module, how do I create a conditional that will do something
based on whether or not another module has been loaded?
Suppose I have the following:
import foo
import foobar
print foo()
print foobar()
########### foo.py
def foo:
return 'foo'
########### foobar.py
def foobar:
if foo.has_been_loaded(): # This is not right!
return foo() + 'bar' # This might need to be foo.foo() ?
else:
return 'bar'
If someone is using foo module, I want to take advantage of its
features and use it in foobar, otherwise, I want to do something else.
In other words, I don't want to create a dependency of foobar on foo.
My failed search for solving this makes me wonder if I'm approaching
this all wrong.
Thanks in advance,
Pete
More information about the Python-list
mailing list