Can't define __call__ within __init__?
breamoreboy at yahoo.co.uk
Wed Mar 10 14:40:19 CET 2010
Neal Becker wrote:
> Want to switch __call__ behavior. Why doesn't this work? What is the
> correct way to write this?
> class X (object):
> def __init__(self, i):
> if i == 0:
> def __call__ (self):
> return 0
> def __call_ (self):
> return 1
> x = X(0)
> TypeError: 'X' object is not callable
I think it's because X has already been constructed when __init__ is
called, so __new__ is the place for your conditional code.
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