itertools: problem with nested groupby, list()

[Ulrich Eckhardt]

Nico Schlömer wrote:
> So when I go like
> 
> for item in list:
>     item[1].sort()
> 
> I actually modify *list*? I didn't realize that; I thought it'd just
> be a copy of it.

No, I misunderstood your code there. Modifying the objects inside the list
is fine, but I don't thing you do that, provided the items in the list
don't contain references to the list itself.

Good luck!

Uli

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