accessing superclass methods from subclass
Bruno Desthuilliers
bruno.42.desthuilliers at websiteburo.invalid
Wed May 12 03:25:23 EDT 2010
Chris Rebert a écrit :
(snip)
> Here is how I would rewrite your example:
>
> class Shape(object):
> def __init__(self, x=0, y=0):
> self.x = x
> self.y = y
>
> @property
> def location(self):
> return (self.x, self.y)
>
> @location.setter
> def location(self, val):
> self.x, self.y = val
Not necessary but helps documenting the expected interface:
def draw(self):
raise NotImplementedError("Abstract method")
> class Square(Shape):
> def __init__(self,size):
> super(Square, self).__init__()
> self.size = size
Why can't I specify a Square location ??? This looks rather inconsistant
and inconveniant to me...
def __init__(self, x=0, y=0, size=0):
super(Square, self).__init__(x, y)
self.size = size
> def draw(self):
> x, y = self.location
> # code to draw shape from location[0],location[1] at size size
> # etc...
>
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