parsing XML

[kaklis at gmail.com]

On May 14, 6:22 pm, Stefan Behnel <stefan... at behnel.de> wrote:
> kak... at gmail.com, 14.05.2010 16:57:
>
> > Hi to all, let's say we have the following Xml
> > <team>
> >    <player name='Mick Fowler' age='27' height='1.96m'>
> >      <points>17.1</points>
> >      <rebounds>6.4</rebounds>
> >    </player>
> >    <player name='Ivan Ivanovic' age='29' height='2.04m'>
> >      <points>15.5</points>
> >      <rebounds>7.8</rebounds>
> >    </player>
> > </team>
>
> > How can i get the players name, age and height?
>
> Here's an overly complicated solution, but I thought that an object
> oriented design would help here.
>
>    import xml.etree.ElementTree as ET
>
>    class Player(object):
>       def __init__(self, name, age, height):
>           self.name, self.age, self.height = name, age, height
>
>    attributes = ['name', 'age', 'height']
>
>    players = []
>    for _, element in ET.iterparse("teamfile.xml"):
>        if element.tag == 'player':
>            players.append(
>                Player(*[ element.get(attr) for attr in attributes ]))
>
>    for player in players:
>        print player.name, player.age, player.height
>
> Stefan

Thanks stefan!

A.K.