Like __getattr__ but with args and kwargs as well
Chris Rebert
clp2 at rebertia.com
Fri May 28 13:43:33 EDT 2010
On Fri, May 28, 2010 at 10:08 AM, Giampaolo Rodolà <g.rodola at gmail.com> wrote:
> I know, the title doesn't say much, but I had no better ideas. =)
> I have a class within a serie of redundant methods, which looks like this:
>
> class MixedAuthorizer:
>
> def __init__(self, *args):
> # expected a list of class instances
> self.authorizers = args
>
> def get_home(self, user):
> for auth in self.authorizers:
> if not auth.has_user(user):
> continue
> return auth.get_home(user)
> return ""
>
> def get_password(self, user):
> for auth in self.authorizers:
> if not auth.has_user(user):
> continue
> return auth.get_password(user)
> return ""
>
> # follows a long list of get_* methods as above
> ...
>
>
> Considering that I always do the same thing (iterate over a list of
> objects -> call obj.has_user() -> call obj.get_*()) I would like to
> know if there's a more compact way to do that.
> What I basically need is something like __getattr__ but which provides
> the arguments and eventually the keyword arguments a method has been
> called with, other than just its name.
> Actually I'm not even sure whether Python can reach such a level of
> dynamism but I wanted to give it a try anyway.
> Is there a way to do such a thing?
There's no such "über-__getattr__", but with some indirection we can
achieve much the same effect:
#Note: Completely untested
from functools import partial
class Whatever(object):
def _getter(self, _name, user, *args, **kwds):
# I assume your actual code will use the *args and **kwds
for auth in self.authorizers:
if not auth.has_user(user):
continue
return getattr(auth, _name)(user)
return ""
def __getattr__(self, name):
if name.startswith("get_"):
return partial(self._getter, _name=name)
else:
raise AttributeError
Cheers,
Chris
--
http://blog.rebertia.com
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