if the else short form

[Mel]

BartC wrote:

> 
> 
> "Lawrence D'Oliveiro" <ldo at geek-central.gen.new_zealand> wrote in message
> news:i8j0dg$lh7$2 at lust.ihug.co.nz...
>> In message <i8i1h8$dcl$1 at news.eternal-september.org>, BartC wrote:
> 
>>> x = ("One","Two","Three") [i-1]
>>>
>>> While this works for i = 1,2,3, it goes funny for i=0,-1,-2, and
>>> generates
>>> an error for the rest ...
>>
>> x = {1 : "One", 2 : "Two", 3 : "Three"}.get(i, "None Of The Above")
> 
> Yes, I expected Python to come up with something (it always does).
> 
> However,  as I mentioned, one problem here is having to evaluate all the
> items in the list before selecting one:
> 
> def fna():
>         print "FNA CALLED"
>         return "One"
> def fnb():
>         print "FNB CALLED"
>         return "Two"
> def fnc():
>         print "FNC CALLED"
>         return "Three"
> 
> i=16
> x = {1 : fna(), 2 : fnb(), 3 : fnc()}.get(i, "None Of The Above")
> print x
> 
> Other than efficiency concerns, sometimes you don't want the extra
> side-effects.
> 
> Probably there are workarounds here too,

The workaround would be (untested)
x = {1: fna, 2: fnb, 3: fnc}.get(i, lambda: "None Of The Above") ()

	Mel.