pyqt unhandled RuntimeError \"no access to protected functions or signals for objects not created from Python

luca72 lucaberto at libero.it
Fri Sep 3 09:58:12 CEST 2010


Hello i have also write to pyqt mailing list but maybe you can help me
to solve this question:
I have write a tcpserver but wheni try to read by the signal
readyRead() e get the error
    this the part of the program:
    def nuova_connessione(self):
            print 'Nuova connessione'
            self.nuovo_socket =
self.mio_server.nextPendingConnection()
            print self.nuovo_socket
            self.connect(self.nuovo_socket,
QtCore.SIGNAL("connected()"), self.
    connessione)
            self.connect(self.nuovo_socket,
QtCore.SIGNAL("readyRead()"), self.
    leggo_risposta)
            self.connect(self.nuovo_socket,
QtCore.SIGNAL("disconnected"), self.
    sconnesso)
            self.connect(self.nuovo_socket,
QtCore.SIGNAL("error(Qtcore.
    QAbsatctSocket::SocketError)"), self.server_errore)

def leggo_risposta(self):
           cosa_leggo = self.nuovo_socket.readData(self.nuovo_socket.
    bytesAvailable())
    can you help me
    Thanks



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