Calling an arbitrary function with the right arguments

Jean-Michel Pichavant jeanmichel at sequans.com
Mon Sep 27 11:08:05 CEST 2010


John O'Hagan wrote:
> How to call a function with the right arguments without knowing in advance 
> which function? For example:
>
> import random
>
> def f1():
>     pass
>
> def f2(foo):
>     pass
>
> def f3(foo, bar):
>     pass
>
> foo=random.choice((1,2,3))
> bar=random.choice((1,2,3))
>
> myfunc=random.choice((f1, f2, f3))
>
> How to call myfunc with the right arguments?
> I've been doing it this way:
>
> f1.args=()
> f2.args=('foo',)
> f3.args=('foo', 'bar')
>
> args=[vars()[i] for i in myfunc.args]
>
> myfunc(*args)
>
> But it seems redundant to manually tag the functions with their own arguments' 
> names, and I don't like using vars(). Is there a nicer pattern? 
>
> Regards,
>
> John
>
>   
Hi,

func, args = random.choice(((f1, ()), (f2, (foo,)), (f3, (foo, bar))))
func(*args)

JM



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