a better way to invert a list?
scattered
tooscattered at gmail.com
Tue Apr 5 23:17:33 CEST 2011
Greetings,
I've been playing around (in Python 3.1) with permutations of
0,1,...,n-1, represented by lists, p, of length n, where p[i] = the
image of i under the permutation. I wanted to be able to calculate the
inverse of such a permutation, and came up with the following succint
but not quite readable function:
def invert(p):
return [ j for (i,j) in sorted(zip(p,range(len(p))))]
I rejected the obvious [p.index(i) for i in range(len(p))] since that
seems an inefficient way to sort. Is there a better way to do this?
Another question about my code: What is more idiomatic, [ j for (i,j)
in ...] or [ x[1] for x in ... ]? I find the former more readable.
But it makes bindings for i and doesn't use them - which can't be very
efficient. In Haskell or ML, you can use patterns that contain wild
cards that play a role in the pattern-matching but don't establish any
binding. Can that be done in Python?
Thanks
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