De-tupleizing a list

[Algis Kabaila]

On Tuesday 26 April 2011 22:19:08 Gnarlodious wrote:
> On Apr 25, 10:59 pm, Steven D'Aprano wrote:
> > In Python 3, map becomes lazy and returns an iterator
> > instead of a list, so you have to wrap it in a call to
> > list().
> 
> Ah, thanks for that tip. Also works for outputting a tuple:
> list_of_tuples=[('0A',), ('1B',), ('2C',), ('3D',)]
> 
> #WRONG:
> (x for (x,) in list_of_tuples)
> <generator object <genexpr> at 0x1081ee0>
> 
> #RIGHT:
> tuple(x for (x,) in list_of_tuples)
> 
> Thanks everyone for the abundant help.
> 
> -- Gnarlie

I think you already have the following:
>>> t = [('0A',), ('1B',), ('2C',), ('3D',)]
>>> ls = [v[0] for v in t]
>>> ls
['0A', '1B', '2C', '3D']
>>> 

I would prefer that to using a ready made module,  as it would 
be quicker than learning about the module,  OTH, learning about 
a module may be useful for other problems.  A standard dilema...

The above quote of code is in Idle3, running Python 3.1.

OldAl.
-- 
Algis
http://akabaila.pcug.org.au/StructuralAnalysis.pdf