Calling super() in __init__ of a metaclass
Eli Bendersky
eliben at gmail.com
Sat Aug 6 03:34:48 EDT 2011
Consider this standard metaclass definition:
class MyMetaclass(type):
def __init__(cls, name, bases, dct):
super(MyMetaclass, cls).__init__(name, bases, dct)
# do meta-stuff
class Foo(object):
__metaclass__ = MyMetaclass
The call "super(MyMetaclass, cls)" should returns the parent of
MyMetaclass here. But the 'cls' passed into this __init__ is *not*
MyMetaclass, but rather the created class - i.e. Foo. So how does
"super" get to the parent of MyMetaclass using this information? The
documentation of "super" says:
If the second argument is a type, issubclass(type2, type) must be
true (this is useful for classmethods).
Yes, 'cls' is a type (it's "class Foo"), but no, it's not a subclass
of MyMetaclass, so this doesn't help.
Eli
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